$A$ metallic conductor of irregular cross-section is as shown in the figure. $A$ constant potential difference is applied across the ends $(1)$ and $(2)$. Then:
- Athe current at the cross-section $P$ equals the current at the cross-section $Q$
- Bthe electric field intensity at $P$ is less than that at $Q$
- Cthe rate of heat generated per unit time at $Q$ is greater than that at $P$
- DAll of the above
Explore More
Similar Questions
Which of the following circuits follows Ohm's law?
Medium
View SolutionTotal $emf$ produced in a thermocouple does not depend on
In the Seebeck series,$Sb$ appears before $Bi$. In an $Sb-Bi$ thermocouple,the current flows from:
Medium
View Solution$A$ cell sends a current through a resistance $R_1$ for time $t$. Now,the same cell sends a current through a resistance $R_2$ for the same time $t$. If the heat produced in both cases is the same,then the internal resistance of the cell is:
Difficult
View SolutionThe ends of an element of zinc wire are kept at a small temperature difference $\Delta T$ and a small current $I$ is passed through the wire. Then, the heat developed per unit time
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo