Ammonia under a pressure of 15 atm at 27 ^{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction is $2NH_3 \rightleftharpoons N_2 + 3H_2$.Initial moles: $a$,$0$,$0$.Moles at equilibrium: $(a - 2x)$,$x$,$3x$.Total moles at equilibr

Vedclass · Accepted Answer

$61.3$

Vedclass · Answer

(B) The reaction is $2NH_3 ightleftharpoons N_2 + 3H_2$.Initial moles: $a$,$0$,$0$.Moles at equilibrium: $(a - 2x)$,$x$,$3x$.Total moles at equilibrium: $(a - 2x) + x + 3x = a + 2x$.Initial pressure of $a$ moles of $NH_3$ at $27 \ ^{\circ}C$ $(300 \ K)$ is $15 \ atm$.Let $p$ be the pressure of $a$ moles of $NH_3$ at $347 \ ^{\circ}C$ $(620 \ K)$.Using $\frac{P_1}{T_1} = \frac{P_2}{T_2}$ (at constant volume),$\frac{15}{300} = \frac{p}{620}$,which gives $p = 31 \ atm$.Since $P \propto n$ at constant $V$ and $T$,the initial pressure $P_i = 31 \ atm$ corresponds to $a$ moles.The final pressure $P_f = 50 \ atm$ corresponds to $(a + 2x)$ moles.Therefore,$\frac{a + 2x}{a} = \frac{50}{31}$.$1 + \frac{2x}{a} = \frac{50}{31} \implies \frac{2x}{a} = \frac{50}{31} - 1 = \frac{19}{31}$.Percentage of $NH_3$ decomposed $= \frac{2x}{a} 	imes 100 = \frac{19}{31} 	imes 100 \approx 61.29 \% \approx 61.3 \%$.

Similar Questions

The equilibrium constant at $298 \ K$ for a reaction $A + B \rightleftharpoons C + D$ is $100$. If the initial concentration of all the four species were $1 \ M$ each,then the equilibrium concentration of $D$ (in $mol \ L^{-1}$) will be:

$2 \ mol$ of $N_2O_{4(g)}$ is kept in a closed container at $298 \ K$ and under $1 \ atm$ pressure. It is heated to $596 \ K$ when $20 \%$ by mass of $N_2O_{4(g)}$ decomposes to $NO_2$. The resulting pressure is (in $atm$)

For the reaction $N_2 + O_2 \rightleftharpoons 2NO$ at $300 \, ^\circ C$,the value of $K_c$ is $9 \times 10^{-4}$. If equivalent amounts of $N_2$ and $O_2$ are used,what is the concentration of $NO$ at equilibrium (in terms of $a$) (in $, a$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module