Ammonolysis of alkyl halides followed by treatment with $NaOH$ solution can be used to prepare primary,secondary,and tertiary amines. The purpose of $NaOH$ in the reaction is:
- Ato remove basic impurities
- Bto activate $NH_3$ used in the reaction
- Cto remove acidic impurities
- Dto increase the reactivity of alkyl halide
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Similar Questions
Hydrolysis of alkyl isocyanide yields:
Difficult
View SolutionName the products in the acid-base reaction :
$(a)$ $CH_3CH_2NH_2 + HI$
$(b)$ $(CH_3)_3N + HBr$
$(a)$ $CH_3CH_2NH_2 + HI$
$(b)$ $(CH_3)_3N + HBr$
Difficult
View Solution$A$ compound with molecular mass $180$ is acylated with $CH_3COCl$ to get a compound with molecular mass $390$. The number of amino groups present per molecule of the former compound is:
DifficultJEE MAIN 2013
View Solution$A$ primary amine,$RNH_2$ can be reacted with $CH_3-X$ to get a secondary amine,$RNHCH_3$,but the disadvantage is that $3^o$ amine and quaternary ammonium salts are also obtained as side products. Can you suggest a method where $RNH_2$ forms only $2^o$ amine?
Suppose the following reaction:
$CH_3-CH(CH_3)-COOH + CH_3-NH_2$ $\rightarrow 'A'$ $\xrightarrow{\Delta} 'B'$ $\xrightarrow{LiAlH_4 (excess)} 'C'$
The final product '$C$' will be:
$CH_3-CH(CH_3)-COOH + CH_3-NH_2$ $\rightarrow 'A'$ $\xrightarrow{\Delta} 'B'$ $\xrightarrow{LiAlH_4 (excess)} 'C'$
The final product '$C$' will be:
Difficult
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