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(D) Geometrical isomerism in coordination complexes depends on the arrangement of ligands around the central metal atom.$(a) [Pt(NH_3)_3 Cl]^+$ is a s

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$(c)$ and $(d)$

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(D) Geometrical isomerism in coordination complexes depends on the arrangement of ligands around the central metal atom.$(a) [Pt(NH_3)_3 Cl]^+$ is a square planar complex of the type $[MA_3B]$,which does not show geometrical isomerism.$(b) [Pt(NH_3) Cl_5]^-$ is an octahedral complex of the type $[MA_5B]$,which does not show geometrical isomerism.$(c) [Pt(NH_3)_2 Cl(NO_2)]$ is a square planar complex of the type $[MA_2BC]$. It can exist in cis and trans forms.$(d) [Pt(NH_3)_4 ClBr]^{2+}$ is an octahedral complex of the type $[MA_4BC]$. It can exist in cis and trans forms.Therefore,complexes $(c)$ and $(d)$ exhibit geometrical isomerism.

Among $(a) - (d)$,the complexes that can display geometrical isomerism are:
$(a) [Pt(NH_3)_3 Cl]^+$
$(b) [Pt(NH_3) Cl_5]^-$
$(c) [Pt(NH_3)_2 Cl(NO_2)]$
$(d) [Pt(NH_3)_4 ClBr]^{2+}$

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Among $(a) - (d)$,the complexes that can display geometrical isomerism are:$(a) [Pt(NH_3)_3 Cl]^+$$(b) [Pt(NH_3) Cl_5]^-$$(c) [Pt(NH_3)_2 Cl(NO_2)]$$(d) [Pt(NH_3)_4 ClBr]^{2+}$