Among $H_2, He_2^{+}, Li_2, Be_2, B_2, C_2, N_2, O_2^{-}$,and $F_2$,the number of diamagnetic species is (Atomic numbers: $H=1, He=2, Li=3, Be=4, B=5, C=6, N=7, O=8, F=9$)

  • A
    $4$
  • B
    $8$
  • C
    $6$
  • D
    $5$

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Which of the following has the least bond energy?

When $\psi_A$ and $\psi_B$ are the wave functions of atomic orbitals,then $\sigma^*$ is represented by :

According to $MO$ theory,the number of species/ions from the following having identical bond order is $.........$
$CN^{-}, NO^{+}, O_{2}, O_{2}^{+}, O_{2}^{2+}$

After understanding the assertion and reason, choose the correct option.
Assertion : In the bonding molecular orbital $(MO)$ of $H_2,$ electron density is increased between the nuclei.
Reason : The bonding $MO$ is $\psi_A + \psi_B,$ which shows destructive interference of the combining electron waves.

Among the following species,the diamagnetic molecule is

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