Among Fe^{3+}, Pb^{2+}, Cu^{2+}, and Mn^{2+}, | vedclass

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(D) In qualitative inorganic analysis, metal ions are classified into groups based on their precipitation reactions.$Pb^{2+}$ and $Cu^{2+}$ belong to

Vedclass · Accepted Answer

+$7$

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(D) In qualitative inorganic analysis, metal ions are classified into groups based on their precipitation reactions.$Pb^{2+}$ and $Cu^{2+}$ belong to Group $II$ and precipitate as sulfides in an acidic medium.$Fe^{3+}$ belongs to Group $III$ and precipitates as $Fe(OH)_3$ in the presence of $NH_4OH$ and $NH_4Cl$.$Mn^{2+}$ belongs to Group $IV$ and precipitates as $MnS$ when $H_2S$ is passed through an alkaline solution (in the presence of $NH_4OH$).Therefore, $Mn^{2+}$ is the ion that precipitates under the given conditions.The electronic configuration of Manganese $(Mn)$ is $[Ar] 3d^5 4s^2$. It can lose all $7$ valence electrons to achieve its highest oxidation state of $+7$, as seen in compounds like $KMnO_4$.

Among $Fe^{3+}$, $Pb^{2+}$, $Cu^{2+}$, and $Mn^{2+}$, identify the one that gets precipitated out while passing $H_2S$ gas in the presence of $NH_4OH$ as a group reagent. The highest possible oxidation state of the corresponding metal is:

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