Among the compounds A and B with molecular fo | vedclass

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(A) The boiling point of a compound depends on the intermolecular forces present. Alcohols possess $-OH$ groups,which allow for extensive intermolecul

Vedclass · Accepted Answer

$A$ = $1,3,5-$tris(hydroxymethyl)cyclohexane,$B$ = $1,3,5-$trimethoxycyclohexane

Vedclass · Answer

(A) The boiling point of a compound depends on the intermolecular forces present. Alcohols possess $-OH$ groups,which allow for extensive intermolecular hydrogen bonding,leading to significantly higher boiling points compared to ethers,which lack such hydrogen bonding. Compound $A$ is $1,3,5-	ext{tris(hydroxymethyl)cyclohexane}$,which contains three $-OH$ groups,facilitating strong intermolecular hydrogen bonding. Compound $B$ is $1,3,5-	ext{trimethoxycyclohexane}$,which is an ether and lacks hydrogen bonding. Therefore,$A$ has a higher boiling point than $B$.

Among the compounds $A$ and $B$ with molecular formula $C_9H_{18}O_3$,$A$ has a higher boiling point than $B$. The possible structures of $A$ and $B$ are

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