Among the following,the compound which underg | vedclass

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(C) The rate of solvolysis is directly proportional to the stability of the carbocation intermediate formed after the departure of the leaving group $

Vedclass · Accepted Answer

$Me-CH(Br)-CH(CH_3)-Ph$

Vedclass · Answer

(C) The rate of solvolysis is directly proportional to the stability of the carbocation intermediate formed after the departure of the leaving group $(Br^-)$.In option $C$,the compound is $Me-CH(Br)-CH(CH_3)-Ph$. Upon the loss of $Br^-$,it forms a secondary carbocation adjacent to a phenyl group and a methyl group.This carbocation is stabilized by the resonance effect of the phenyl group and the inductive effect $(+I)$ of the methyl group,making it the most stable among the given options.Therefore,the compound in option $C$ undergoes the fastest solvolysis.

Among the following,the compound which undergoes the fastest solvolysis is

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