Among the following,the correct statement is

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(A) . $A$ dilute aqueous solution of $NH_3$ exists as $NH_4OH$,which dissociates as: $NH_4OH \rightleftharpoons NH_4^+ + OH^-$. On adding solid ammoni

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$pH$ decreases when solid ammonium chloride is added to a dilute aqueous solution of $NH_3$

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(A) . $A$ dilute aqueous solution of $NH_3$ exists as $NH_4OH$,which dissociates as: $NH_4OH \rightleftharpoons NH_4^+ + OH^-$. On adding solid ammonium chloride $(NH_4Cl)$,it dissociates completely: $NH_4Cl \rightarrow NH_4^+ + Cl^-$. Due to the common ion effect of $NH_4^+$,the equilibrium shifts to the left,decreasing the concentration of $OH^-$. Since $pOH = -\log[OH^-]$,a decrease in $[OH^-]$ increases $pOH$,which in turn decreases the $pH$ $(pH = 14 - pOH)$.

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