Among the following,the plot that correctly r | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The principle of conductometric titration is based on the fact that during the titration,one of the ions is replaced by another,and these two ions

Vedclass · Accepted Answer

Plot $(b)$

Vedclass · Answer

(B) The principle of conductometric titration is based on the fact that during the titration,one of the ions is replaced by another,and these two ions differ in their ionic conductivity.In the conductometric titration of $0.05 \ M \ H_2SO_4$ with $0.1 \ M \ NH_4OH$,initially,the highly mobile $H^+$ ions are neutralized by $OH^-$ ions to form $H_2O$ and are replaced by less mobile $NH_4^+$ ions. This leads to a decrease in conductance up to the equivalence point.After the equivalence point,the addition of excess weak electrolyte $NH_4OH$ does not significantly increase the conductance because it is weakly dissociated.Therefore,the plot showing a decrease in conductance followed by a nearly constant conductance is the correct representation.

Among the following,the plot that correctly represents the conductometric titration of $0.05 \ M \ H_2SO_4$ with $0.1 \ M \ NH_4OH$ is

Similar Questions

Which of the following concentrations of $KCl$ solution has the lowest value of equivalent conductivity (in $M$)?

$\Lambda_{m(HAc)}^0$ is equal to . . . . . . .

The property which decreases with dilution is:

Explain the measurement and calculation of the resistivity of an electrolytic solution.

The resistivity of a $0.8 \ M$ solution of an electrolyte is $5 \times 10^{-3} \ \Omega \ cm$. Its molar conductivity is $..... \times 10^4 \ \Omega^{-1} \ cm^2 \ mol^{-1}$. (Nearest integer)

Vedclass Test Series

Exam Paper Generator

Online Exam Module