Among the following,the species having square | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the geometry,we analyze the hybridization and lone pairs of the central atom:$1$. $XeF_4$: $Xe$ has $8$ valence electrons. It forms $

Vedclass · Accepted Answer

$(i)$ and $(iv)$

Vedclass · Answer

(A) To determine the geometry,we analyze the hybridization and lone pairs of the central atom:$1$. $XeF_4$: $Xe$ has $8$ valence electrons. It forms $4$ bonds with $F$ and has $2$ lone pairs. Steric number = $4 + 2 = 6$ ($sp^3d^2$ hybridization). Due to $2$ lone pairs,it adopts a square planar geometry.$2$. $SF_4$: $S$ has $6$ valence electrons. It forms $4$ bonds with $F$ and has $1$ lone pair. Steric number = $4 + 1 = 5$ ($sp^3d$ hybridization). It adopts a see-saw geometry.$3$. $[NiCl_4]^{2-}$: $Ni^{2+}$ is a $d^8$ ion. With a weak field ligand $(Cl^-)$,it undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry.$4$. $[PtCl_4]^{2-}$: $Pt^{2+}$ is a $5d$ series metal ion. It forms square planar complexes due to high crystal field splitting,resulting in $dsp^2$ hybridization.Therefore,the species with square planar geometry are $(i)$ $XeF_4$ and $(iv)$ $[PtCl_4]^{2-}$.

Among the following,the species having square planar geometry for the central atom are:
$(i)$ $XeF_4$
$(ii)$ $SF_4$
$(iii)$ $[NiCl_4]^{2-}$
$(iv)$ $[PtCl_4]^{2-}$

Similar Questions

Which type of atomic orbitals hybridize to form a square planar complex?

Which of the following is a square planar complex ion?

The $Cl-Co-Cl$ bond angle values in a $fac-[Co(NH_3)_3Cl_3]$ complex is/are:

The hybridization of $Fe$ in $K_3[Fe(CN)_6]$ is

Reaction of $[Co(H_2O)_6]^{2+}$ with excess ammonia and in the presence of oxygen results into a diamagnetic product. Number of electrons present in $t_{2g}$-orbitals of the product is $.....$ .

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Among the following,the species having square planar geometry for the central atom are:$(i)$ $XeF_4$$(ii)$ $SF_4$$(iii)$ $[NiCl_4]^{2-}$$(iv)$ $[PtCl_4]^{2-}$