Among the following,which is the strongest ox | vedclass

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(A) The strength of an oxidizing agent is determined by its reduction potential value. $A$ higher positive reduction potential indicates a stronger ox

Vedclass · Accepted Answer

$Mn^{3+}$

Vedclass · Answer

(A) The strength of an oxidizing agent is determined by its reduction potential value. $A$ higher positive reduction potential indicates a stronger oxidizing agent.Comparing the standard reduction potentials $(E^{0})$ for the given ions:$E^{0}_{Mn^{3+}/Mn^{2+}} = +1.51 \, V$$E^{0}_{Fe^{3+}/Fe^{2+}} = +0.77 \, V$$E^{0}_{Ti^{3+}/Ti^{2+}} = -0.37 \, V$$E^{0}_{Cr^{3+}/Cr^{2+}} = -0.41 \, V$Since $Mn^{3+}$ has the highest positive reduction potential,it is the strongest oxidizing agent among the given options.

Among the following,which is the strongest oxidizing agent?

Similar Questions

Which transition metal reduces steam to evolve hydrogen?

Which of the following statements is not correct?

The set of correct statements is:
$(i)$ Manganese exhibits $+7$ oxidation state in its oxide.
$(ii)$ Ruthenium and Osmium exhibit $+8$ oxidation state in their oxides.
$(iii)$ $Sc$ shows $+4$ oxidation state which is oxidizing in nature.
$(iv)$ $Cr$ shows oxidizing nature in $+6$ oxidation state.

How would you account for the increasing oxidising power in the series $VO_2^+ < Cr_2O_7^{2-} < MnO_4^-$?

Correct order of oxidising nature is

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