Among the following series of transition meta | vedclass

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(D) The electronic configuration of the neutral atoms is:$Ti (Z=22): [Ar] 3d^2 4s^2$$V (Z=23): [Ar] 3d^3 4s^2$$Cr (Z=24): [Ar] 3d^5 4s^1$$Mn (Z=25): [

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$Ti^{2+}, V^{3+}, Cr^{4+}, Mn^{5+}$

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(D) The electronic configuration of the neutral atoms is:$Ti (Z=22): [Ar] 3d^2 4s^2$$V (Z=23): [Ar] 3d^3 4s^2$$Cr (Z=24): [Ar] 3d^5 4s^1$$Mn (Z=25): [Ar] 3d^5 4s^2$For the ions in option $(d)$:$Ti^{2+}: [Ar] 3d^2$$V^{3+}: [Ar] 3d^2$$Cr^{4+}: [Ar] 3d^2$$Mn^{5+}: [Ar] 3d^2$Since $[Ar]$ corresponds to $1s^2 2s^2 2p^6 3s^2 3p^6$,all these ions possess the $3d^2$ configuration outside the $3p^6$ shell.

Among the following series of transition metal ions,the one in which all the metal ions have $3d^2$ electronic configuration (excluding the $3p^6$ core) is (Atomic number: $Ti=22, V=23, Cr=24, Mn=25$)

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