Among the following species,the one which causes the highest $CFSE, \Delta _0$ as a ligand is

  • A
    $CN^{-}$
  • B
    $NH_3$
  • C
    $F^{-}$
  • D
    $CO$

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Similar Questions

Match List-$I$ with List-$II$:
List-$I$ (Complex) List-$II$ ($CFSE$ in $\Delta_0$)
$A$. $[Ti(H_2O)_6]^{2+}$ $I$. $-1.2$
$B$. $[V(H_2O)_6]^{2+}$ $II$. $-0.8$
$C$. $[Mn(H_2O)_6]^{3+}$ $III$. $-0.6$
$D$. $[Fe(H_2O)_6]^{3+}$ $IV$. $0$

Match the following complexes in List-$I$ with their electronic configurations in List-$II$.
List-$I$ (Complex)List-$II$ (Electronic configuration of metal/ion)
$A. [Co(NH_3)_6]^{3+}$$I. t_{2g}^5 e_g^0$
$B. [CoF_6]^{3-}$$II. t_{2g}^6 e_g^0$
$C. [Ni(CO)_4]$$III. t_{2g}^4 e_g^2$
$D. [Fe(CN)_6]^{3-}$$IV. t^4 e^6$

Explain the color in coordination compounds.

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Match the $LIST$-$I$ with $LIST$-$II$:
List-$I$ (Electronic configuration of tetrahedral metal ion) List-$II$ (Crystal Field Stabilization Energy $(\Delta_t)$)
$A$. $d^2$ $I$. $-0.6$
$B$. $d^4$ $II$. $-0.8$
$C$. $d^6$ $III$. $-1.2$
$D$. $d^8$ $IV$. $-0.4$

$CuSO_4 \cdot 5 H_2O$ is blue in colour while $CuSO_4$ is colourless. Why?

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