Among the following,the appropriate reactants | vedclass

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Question

(A) The preparation of $1$-ethyl cyclohexanol involves the acid-catalyzed hydration of ethylidene cyclohexane. $1$. Ethylidene cyclohexane $(C_8H_{14}

Vedclass · Accepted Answer

Ethylidene cyclohexane + $H_3O^+$

Vedclass · Answer

(A) The preparation of $1$-ethyl cyclohexanol involves the acid-catalyzed hydration of ethylidene cyclohexane. $1$. Ethylidene cyclohexane $(C_8H_{14})$ reacts with $H_3O^+$ (acid catalyst). $2$. The double bond is protonated to form a stable tertiary carbocation at the $1$-position of the cyclohexane ring. $3$. Water then attacks the carbocation,followed by deprotonation to yield $1$-ethyl cyclohexanol. Thus,the correct reactants are ethylidene cyclohexane and $H_3O^+$.

Among the following,the appropriate reactants for the preparation of $1$-ethyl cyclohexanol are:

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