Among the following,which is the strongest ox | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The strength of an oxidising agent is determined by its ability to gain electrons,which is related to its reduction potential. Fluorine $(F_2)$ ha

Vedclass · Accepted Answer

$F_2$

Vedclass · Answer

(D) The strength of an oxidising agent is determined by its ability to gain electrons,which is related to its reduction potential. Fluorine $(F_2)$ has the highest electronegativity and the highest standard reduction potential among the halogens. As we move down the group,the electronegativity decreases,making it harder to gain electrons. Therefore,$F_2$ is the strongest oxidising agent as it is reduced most readily to the $F^-$ ion.

Among the following,which is the strongest oxidising agent?

Similar Questions

Which two of the following salts are used for preparing iodized salt?
$(i) \, KIO_3$ $(ii) \, KI$
$(iii) \, I_2$ $(iv) \, HI$

In the dark,which of the following reacts with hydrogen?

What is the molecular formula of iodic acid?

In the following reaction,identify the nature of the product formed by the complete hydrolysis of $BrF_5$ at $R.T.$:
$BrF_5 + 3H_2O \longrightarrow HBrO_3 + 5HF$

Bromine is obtained commercially from sea water by adding

Vedclass Test Series

Exam Paper Generator

Online Exam Module