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(B) Compounds that are acidic enough to react with aqueous $NaOH$ (a base) to form water-soluble salts are soluble in aqueous $NaOH$. $1$. Cyclohexane

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$4$

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(B) Compounds that are acidic enough to react with aqueous $NaOH$ (a base) to form water-soluble salts are soluble in aqueous $NaOH$. $1$. Cyclohexanecarboxylic acid (contains $-COOH$ group,acidic). $2$. Phenol (contains phenolic $-OH$ group,acidic). $3$. $4$-(Dimethylamino)phenol (contains phenolic $-OH$ group,acidic). $4$. $1$-Naphthoic acid (contains $-COOH$ group,acidic). Other compounds like $N,N$-dimethylaniline,$2$-ethoxybenzyl alcohol,nitrobenzene,and $1,2$-diethylbenzene are not sufficiently acidic to react with $NaOH$. Therefore,the total number of compounds soluble in aqueous $NaOH$ is $4$.

Amongst the following,the total number of compounds soluble in aqueous $NaOH$ is:

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