The amount of solar energy received on the Ea | vedclass

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Question

(D) The solar constant $S$ is defined as the energy $E$ incident per unit area $A$ per unit time $t$.$S = \frac{E}{A 	imes t}$The dimension of energy

Vedclass · Accepted Answer

$MT^{-3}$

Vedclass · Answer

(D) The solar constant $S$ is defined as the energy $E$ incident per unit area $A$ per unit time $t$.$S = \frac{E}{A 	imes t}$The dimension of energy $E$ is $[ML^{2}T^{-2}]$.The dimension of area $A$ is $[L^{2}]$.The dimension of time $t$ is $[T]$.Substituting these dimensions into the formula:$S = \frac{[ML^{2}T^{-2}]}{[L^{2}] 	imes [T]}$$S = \frac{[ML^{2}T^{-2}]}{[L^{2}T]}$$S = [MT^{-3}]$Thus,the dimension of the solar constant is $[MT^{-3}]$.

Column-$I$	Column-$II$
$(1)$ Torque	$(a)$ $M^1L^1T^{-1}$
$(2)$ Angular momentum	$(b)$ $M^1L^2T^{-1}$
$(3)$ Linear momentum	$(c)$ $M^1L^2T^{-2}$

The amount of solar energy received on the Earth's surface per unit area per unit time is defined as the solar constant. The dimension of the solar constant is:

Similar Questions

Match the physical quantities in Column-$I$ with their corresponding dimensional formulas in Column-$II$.

Column-$I$ Column-$II$

$(1)$ Torque $(a)$ $M^1L^1T^{-1}$

$(2)$ Angular momentum $(b)$ $M^1L^2T^{-1}$

$(3)$ Linear momentum $(c)$ $M^1L^2T^{-2}$

The dimensional formula of a physical quantity is $[M^{a} L^{b} T^{c}]$. Then,that physical quantity is:

The dimensional formula for impulse is

The dimensional formula for latent heat is

The dimensional formula of relative density is

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