An X-ray tube is operated at 50, kV. The mini | vedclass

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(C) The minimum wavelength $(\lambda_{\min})$ produced in an $X$-ray tube is given by the formula: $\lambda_{\min} = \frac{hc}{eV} = \frac{12400}{V(

Vedclass · Accepted Answer

$0.25$

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(C) The minimum wavelength $(\lambda_{\min})$ produced in an $X$-ray tube is given by the formula: $\lambda_{\min} = \frac{hc}{eV} = \frac{12400}{V(	ext{in volts})} \mathring{A}$ (approximately).Using the given potential difference $V = 50\, kV = 50,000\, V$:$\lambda_{\min} = \frac{12375}{50,000} \mathring{A}$.$\lambda_{\min} = 0.2475 \mathring{A}$.Rounding to the nearest given option,we get $\lambda_{\min} \approx 0.25 \mathring{A}$.

An $X$-ray tube is operated at $50\, kV$. The minimum wavelength produced is ....... $\mathring{A}$.

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