An aircraft executes a horizontal loop of rad | vedclass

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(B) Given: Radius $r = 9 \ km = 9000 \ m$. Speed $v = 540 \ km/h = 540 	imes \frac{5}{18} \ m/s = 150 \ m/s$. Acceleration due to gravity $g = 10 \ m

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$\cot^{-1}(4)$

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(B) Given: Radius $r = 9 \ km = 9000 \ m$. Speed $v = 540 \ km/h = 540 	imes \frac{5}{18} \ m/s = 150 \ m/s$. Acceleration due to gravity $g = 10 \ m/s^2$. For a banked aircraft in a horizontal loop, the banking angle $	heta$ is given by the relation: $	an 	heta = \frac{v^2}{rg}$. Substituting the values: $	an 	heta = \frac{150 	imes 150}{9000 	imes 10} = \frac{22500}{90000} = \frac{1}{4}$. Since $	an 	heta = \frac{1}{4}$, we have $\cot 	heta = 4$, which implies $	heta = \cot^{-1}(4)$.

An aircraft executes a horizontal loop of radius $9 \ km$ at a constant speed of $540 \ km/h$. The wings of the aircraft are banked at an angle of (Acceleration due to gravity $g = 10 \ m/s^2$):

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