An airplane flies 400 ,m north and 300 ,m sou | vedclass

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(C) Let the starting point be the origin $(0, 0, 0)$.The airplane flies $400 \,m$ north,so its position is $(0, 400, 0)$.Then it flies $300 \,m$ south

Vedclass · Accepted Answer

$1200$

Vedclass · Answer

(C) Let the starting point be the origin $(0, 0, 0)$.The airplane flies $400 \,m$ north,so its position is $(0, 400, 0)$.Then it flies $300 \,m$ south,so its new position is $(0, 400-300, 0) = (0, 100, 0)$.Finally,it flies $1200 \,m$ upwards,so its final position is $(0, 100, 1200)$.The net displacement is the distance from the origin to the final position:$d = \sqrt{0^2 + 100^2 + 1200^2}$$d = \sqrt{10000 + 1440000}$$d = \sqrt{1450000}$$d = 100 \sqrt{145} \approx 100 	imes 12.04 = 1204.16 \,m$.Rounding to the nearest given option,the net displacement is approximately $1200 \,m$.

An airplane flies $400 \,m$ north and $300 \,m$ south and flies $1200 \,m$ upwards,then the net displacement is (in $\,m$)

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