An alcohol X left( C_5 H_{12} O right) produc | vedclass

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(B) $1$. The Lucas test (conc. $HCl / ZnCl_2$) is used to distinguish between primary, secondary, and tertiary alcohols. Tertiary alcohols react insta

Vedclass · Accepted Answer

$2-$methylbutan$-2-$ol, $3-$methylbutan$-1-$ol

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(B) $1$. The Lucas test (conc. $HCl / ZnCl_2$) is used to distinguish between primary, secondary, and tertiary alcohols. Tertiary alcohols react instantly to produce turbidity.$2$. Alcohol $X$ produces turbidity instantly, meaning it must be a tertiary alcohol. Among the isomers of $C_5 H_{12} O$, $2-$methylbutan$-2-$ol is a tertiary alcohol.$3$. Alcohol $Y$ undergoes dehydration with conc. $H_2 SO_4$ at $443 \ K$ to form an alkene. $3-$methylbutan$-1-$ol is a primary isomer that can undergo this reaction.$4$. Comparing the options, $X$ must be the tertiary alcohol ($2-$methylbutan$-2-$ol) and $Y$ must be the primary alcohol ($3-$methylbutan$-1-$ol).$5$. Therefore, the correct pair is $X = 2-$methylbutan$-2-$ol and $Y = 3-$methylbutan$-1-$ol, which corresponds to option $B$.

Column-$I$	Column-$II$
$A$. Methanol	$p$. Conversion of phenol to salicylic acid
$B$. Kolbe's reaction	$q$. Wood spirit
$C$. Williamson's reaction	$r$. Vapours are passed over heated copper at $573 \ K$
$D$. Conversion of $2^\circ$ alcohol to ketone	$s$. Reaction of alkyl halide with sodium alkoxide

An alcohol $X \left( C_5 H_{12} O \right)$ produces turbidity instantly with conc. $HCl / ZnCl_2$. Isomer $(Y)$ of $X$ undergoes dehydration with conc. $H_2 SO_4$ at $443 \ K$. $X$ and $Y$ respectively are

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