An alkali metal hydride $(NaH)$ reacts with diborane in '$A$' to give a tetrahedral compound '$B$' which is extensively used as a reducing agent in organic synthesis. The compounds '$A$' and '$B$' respectively are
- A$C_{2}H_{6}$ and $C_{2}H_{5}Na$
- B$CH_{3}COCH_{3}$ and $B_{3}N_{3}H_{6}$
- C$C_{6}H_{6}$ and $NaBH_{4}$
- D$(C_{2}H_{5})_{2}O$ and $NaBH_{4}$
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