An alkene X on ozonolysis gives a mixture of | vedclass

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(C) The simplest ketone is acetone,which is $CH_3COCH_3$ (propan$-2-$one).$3-$Pentanone is $CH_3CH_2COCH_2CH_3$.Ozonolysis of an alkene involves break

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$3-$Ethyl$-2-$methylpent$-2-$ene

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(C) The simplest ketone is acetone,which is $CH_3COCH_3$ (propan$-2-$one).$3-$Pentanone is $CH_3CH_2COCH_2CH_3$.Ozonolysis of an alkene involves breaking the $C=C$ double bond and adding oxygen atoms to each carbon.To find the alkene $X$,we combine the two ketones by removing the oxygen atoms and joining the carbonyl carbons with a double bond:$CH_3-C(CH_3)=C(CH_2CH_3)-CH_2CH_3$.The structure is $CH_3-C(CH_3)=C(CH_2CH_3)-CH_2CH_3$.Numbering the chain to give the lowest locants: the longest chain has $6$ carbons (hexane).The double bond is at position $2$.There is a methyl group at position $2$ and an ethyl group at position $3$.Thus,the $IUPAC$ name is $3-$ethyl$-2-$methylhex$-2-$ene. However,checking the options,the structure $CH_3-C(CH_3)=C(CH_2CH_3)-CH_2CH_3$ corresponds to $3-$ethyl$-2-$methylhex$-2-$ene. Re-evaluating the options provided,option $C$ is $3-$ethyl$-2-$methylpent$-2-$ene,which would yield $3-$pentanone and acetone if the structure was $CH_3-C(CH_3)=C(CH_3)-CH_2CH_3$. Given the standard nature of this problem,the correct structure is $3-$ethyl$-2-$methylhex$-2-$ene,but based on the provided options,$C$ is the closest match if we assume a typo in the chain length.

An alkene $X$ on ozonolysis gives a mixture of simplest ketone $(Y)$ and $3-$Pentanone. The $IUPAC$ name of the alkene $X$ is

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