An alkene X (C_4H_8) exhibits geometrical iso | vedclass

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(D) $1$. The alkene $X$ is $but-2-ene$ $(CH_3CH=CHCH_3)$,which exhibits geometrical isomerism.$2$. Oxidation of $but-2-ene$ with acidic $KMnO_4$ yield

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$CH_4$

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(D) $1$. The alkene $X$ is $but-2-ene$ $(CH_3CH=CHCH_3)$,which exhibits geometrical isomerism.$2$. Oxidation of $but-2-ene$ with acidic $KMnO_4$ yields acetic acid $(CH_3COOH)$ as $Y$.$3$. The sodium salt of $Y$ is sodium acetate $(CH_3COONa)$.$4$. Heating sodium acetate with soda lime $(NaOH + CaO)$ undergoes decarboxylation to produce methane $(CH_4)$ as $Z$.

An alkene $X$ $(C_4H_8)$ exhibits geometrical isomerism. Oxidation of $X$ with $KMnO_4 | H^+$ gives $Y$. On heating the sodium salt of $Y$ with a mixture of $NaOH$ and $CaO$,$Z$ is obtained. What is $Z$?

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