An alkyl halide C_3H_7Cl,on reaction with a r | vedclass

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Question

(B) The reaction of alkyl halide $C_3H_7Cl$ with $KCN$ in the presence of $C_2H_5OH$ (an alcoholic solvent) leads to the formation of an alkyl cyanide

Vedclass · Accepted Answer

$KCN/C_2H_5OH$,$CH_3CH_2CH_2CN$

Vedclass · Answer

(B) The reaction of alkyl halide $C_3H_7Cl$ with $KCN$ in the presence of $C_2H_5OH$ (an alcoholic solvent) leads to the formation of an alkyl cyanide (nitrile) as the major product via an $S_N2$ mechanism.$CH_3CH_2CH_2Cl + KCN \xrightarrow{C_2H_5OH} CH_3CH_2CH_2CN + KCl$Here,$X = KCN/C_2H_5OH$ and $Y = CH_3CH_2CH_2CN$.Hydrolysis of alkyl cyanide $(Y)$ yields a carboxylic acid and ammonia gas $(NH_3)$:$CH_3CH_2CH_2CN + 2H_2O + H^+ \rightarrow CH_3CH_2CH_2COOH + NH_3 \uparrow$The ammonia gas $(NH_3)$ released is basic in nature and turns red litmus paper blue.

An alkyl halide $C_3H_7Cl$,on reaction with a reagent $X$ gave the major product $Y$ $(C_4H_7N)$. $Y$ on hydrolysis released a gas,which turns red litmus to blue. What are $X$ and $Y$?

Similar Questions

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