An alpha particle left({ }^{4} Heright) has a | vedclass

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(A) The alpha particle $\left({ }^{4} He\right)$ consists of $2$ protons and $2$ neutrons.The mass of the constituents is $m_{c} = 2(m_{p} + m_{n}) =

Vedclass · Accepted Answer

$27.9$

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(A) The alpha particle $\left({ }^{4} Height)$ consists of $2$ protons and $2$ neutrons.The mass of the constituents is $m_{c} = 2(m_{p} + m_{n}) = 2(1.00783 + 1.00867) = 2(2.01650) = 4.03300 \ amu$.The mass defect $\Delta m$ is given by $\Delta m = m_{c} - m_{He} = 4.03300 - 4.00300 = 0.0300 \ amu$.The binding energy $E$ is calculated using the conversion factor $1 \ amu = 931 \ MeV$.$E = \Delta m 	imes 931 \ MeV/amu = 0.0300 	imes 931 = 27.93 \ MeV$.Thus, the binding energy is approximately $27.9 \ MeV$.

An alpha particle $\left({ }^{4} He\right)$ has a mass of $4.00300 \ amu$. $A$ proton has a mass of $1.00783 \ amu$ and a neutron has a mass of $1.00867 \ amu$. The binding energy of an alpha particle estimated from these data is closest to: (in $MeV$)

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