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(B) The kinetic energy $K$ gained by a charged particle accelerated through a potential difference $V$ is given by the formula $K = qV$.For an alpha p

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$2$

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(B) The kinetic energy $K$ gained by a charged particle accelerated through a potential difference $V$ is given by the formula $K = qV$.For an alpha particle,the charge $q$ is equal to $2e$,where $e$ is the elementary charge.Given,$V = 10^6 \ V$.Substituting the values: $K = (2e) 	imes (10^6 \ V) = 2 	imes 10^6 \ eV$.Since $1 \ MeV = 10^6 \ eV$,we have $K = 2 \ MeV$.

An alpha particle is accelerated through a potential difference of $10^6 \ V$. Its kinetic energy will be $MeV$.

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