An alternating current is given by I = I_A si | vedclass

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(C) The given current is $I = I_A \sin \omega t + I_B \cos \omega t$. We can rewrite this as $I = \sqrt{I_A^2 + I_B^2} \sin(\omega t + \phi)$,where $\

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$\sqrt{\frac{I_A^2 + I_B^2}{2}}$

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(C) The given current is $I = I_A \sin \omega t + I_B \cos \omega t$. We can rewrite this as $I = \sqrt{I_A^2 + I_B^2} \sin(\omega t + \phi)$,where $	an \phi = \frac{I_B}{I_A}$. This represents a sinusoidal current with peak value $I_0 = \sqrt{I_A^2 + I_B^2}$. The r.m.s. value of a sinusoidal current $I = I_0 \sin(\omega t + \phi)$ is given by $I_{rms} = \frac{I_0}{\sqrt{2}}$. Substituting the value of $I_0$,we get $I_{rms} = \frac{\sqrt{I_A^2 + I_B^2}}{\sqrt{2}} = \sqrt{\frac{I_A^2 + I_B^2}{2}}$.

An alternating current is given by $I = I_A \sin \omega t + I_B \cos \omega t$. The r.m.s. current will be

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