An alternating e.m.f. is given by e = e_0 sin | vedclass

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(C) The given equation for alternating e.m.f. is $e = e_0 \sin \omega t$.We want to find the time $t$ when $e = e_0/2$.Substituting this into the equa

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$T/12$

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(C) The given equation for alternating e.m.f. is $e = e_0 \sin \omega t$.We want to find the time $t$ when $e = e_0/2$.Substituting this into the equation: $e_0/2 = e_0 \sin \omega t$.This simplifies to $\sin \omega t = 1/2$.Since $\sin 30^{\circ} = 1/2$ and $30^{\circ} = \pi/6$ radians,we have $\omega t = \pi/6$.We know that $\omega = 2\pi/T$,where $T$ is the time period.Substituting $\omega$ into the equation: $(2\pi/T) \cdot t = \pi/6$.Solving for $t$: $t = (\pi/6) \cdot (T/2\pi) = T/12$.Thus,the time taken is $T/12$.

An alternating e.m.f. is given by $e = e_0 \sin \omega t$. In how much time will the e.m.f. have half its maximum value,if $e$ starts from zero? $(T = \text{time period}, \sin 30^{\circ} = 1/2)$

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