(B) The given equation is $V = 80 \sin(100 \pi t) \cos(100 \pi t)$.Using the trigonometric identity $\sin(2\theta) = 2 \sin \theta \cos \theta$,we can

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(B) The given equation is $V = 80 \sin(100 \pi t) \cos(100 \pi t)$.Using the trigonometric identity $\sin(2\theta) = 2 \sin \theta \cos \theta$,we can rewrite the equation as:$V = 40 \times (2 \sin(100 \pi t) \cos(100 \pi t))$$V = 40 \sin(200 \pi t)$.Comparing this with the standard form of alternating voltage $V = V_0 \sin(\omega t)$,where $V_0$ is the peak voltage,we get $V_0 = 40 \text{ V}$.

Class 12 Physics Alternating Current Alternating Current, Voltage (rms and Average)

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An alternating voltage is represented by $V = 80 \sin(100 \pi t) \cos(100 \pi t) \text{ V}$. The peak voltage is (in $\text{ V}$)

MHT CET 2021 All MHT CET

A
$20$
B
$40$
C
$30$
D
$50$

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Alternating Current

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Alternating Current, Voltage (rms and Average)

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An alternating voltage is represented by $V = 80 \sin(100 \pi t) \cos(100 \pi t) \text{ V}$. The peak voltage is (in $\text{ V}$)

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If an alternating current is given by $i = a \sin(\omega t) + b \cos(\omega t)$,then the $rms$ value of the current is

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