An ammeter with internal resistance $90\,\Omega$ reads $1.85\,A$ when connected in a circuit containing a battery and two resistors $700\,\Omega$ and $410\,\Omega$ in series. The actual current in the circuit (without the ammeter) will be:

  • A
    $1.85\,A$
  • B
    Greater than $1.85\,A$
  • C
    Less than $1.85\,A$
  • D
    None of these

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Voltmeters $V_1$ and $V_2$ are connected in series across a $D.C.$ line. $V_1$ reads $80 \, V$ and has a resistance per volt of $200 \, \Omega/V$. $V_2$ has a total resistance of $32 \, k\Omega$. The line voltage is ............. (in $V$)

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To find the resistance of a galvanometer by the half-deflection method, the following circuit is used with resistances $R_1 = 9970 \,\Omega$, $R_2 = 30 \,\Omega$, and $R_3 = 0 \,\Omega$. The deflection in the galvanometer is $d$. With $R_3 = 107 \,\Omega$, the deflection changes to $\frac{d}{2}$. The galvanometer resistance is approximately ............... $\Omega$.

Two identical moving coil galvanometers have $10 \Omega$ resistance and full scale deflection at $2 \mu A$ current. One of them is converted into a voltmeter of $100 \text{ mV}$ full scale reading and the other into an ammeter of $1 \text{ mA}$ full scale current using appropriate resistors. These are then used to measure the voltage and current in the Ohm's law experiment with $R = 1000 \Omega$ resistor by using an ideal cell. Which of the following statement$(s)$ is/are correct?
$(1)$ The measured value of $R$ will be $980.2 \Omega$.
$(2)$ The resistance of the voltmeter will be $50 \text{ k} \Omega$.
$(3)$ The resistance of the ammeter will be $0.02 \Omega$ (rounded off to the $2^{\text{nd}}$ decimal place).
$(4)$ If the ideal cell is replaced by a cell having internal resistance of $5 \Omega$,then the measured value of $R$ will be more than $1000 \Omega$.

$20\%$ of the main current passes through the galvanometer. If the resistance of the galvanometer is $G$,then the resistance of the shunt will be

$A$ moving coil galvanometer is converted into an ammeter reading up to $0.03\,A$ by connecting a shunt of resistance $4r$ across it,and into an ammeter reading up to $0.06\,A$ when a shunt of resistance $r$ is connected across it. What is the maximum current which can be sent through this galvanometer if no shunt is used?

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