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(B) Given:Frequency of message signal $(f_m) = 1 	ext{ kHz} = 1 	imes 10^3 	ext{ Hz}$.Peak voltage of message signal $(E_m) = 5 	ext{ V}$.Carrier

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$15[1+\frac{1}{3} \sin (2 \pi 10^3 t)] \sin (2 \pi 10^6 t)$

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(B) Given:Frequency of message signal $(f_m) = 1 	ext{ kHz} = 1 	imes 10^3 	ext{ Hz}$.Peak voltage of message signal $(E_m) = 5 	ext{ V}$.Carrier frequency $(f_c) = 1 	ext{ MHz} = 1 	imes 10^6 	ext{ Hz}$.Peak voltage of carrier $(E_c) = 15 	ext{ V}$.The equation of an amplitude modulated wave is given by:$e(t) = E_c [1 + \mu \sin(\omega_m t)] \sin(\omega_c t)$where $\mu = \frac{E_m}{E_c}$ is the modulation index.$\mu = \frac{5}{15} = \frac{1}{3}$.Substituting the values:$e(t) = 15 [1 + \frac{1}{3} \sin(2 \pi f_m t)] \sin(2 \pi f_c t)$$e(t) = 15 [1 + \frac{1}{3} \sin(2 \pi 	imes 10^3 t)] \sin(2 \pi 	imes 10^6 t)$.

An amplitude modulated signal consists of a message signal of frequency $1 \text{ kHz}$ and peak voltage of $5 \text{ V}$,modulating a carrier frequency of $1 \text{ MHz}$ and peak voltage of $15 \text{ V}$. The correct description of this signal is

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