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(C) $1$. From the graph,the amplitude of the signal varies between $8 \, V$ and $10 \, V$. This can be expressed as $A(t) = 9 + 1 \sin(\omega_m t) \,

Vedclass · Accepted Answer

$(9 + \sin(2\pi 	imes 10^4 t)) \sin(2.5\pi 	imes 10^5 t) \, V$

Vedclass · Answer

(C) $1$. From the graph,the amplitude of the signal varies between $8 \, V$ and $10 \, V$. This can be expressed as $A(t) = 9 + 1 \sin(\omega_m t) \, V$.$2$. The time period of the modulating signal (envelope) is $T_m = 100 \, \mu s = 100 	imes 10^{-6} \, s = 10^{-4} \, s$. The angular frequency is $\omega_m = \frac{2\pi}{T_m} = \frac{2\pi}{10^{-4}} = 2\pi 	imes 10^4 \, rad/s$.$3$. The time period of the carrier wave is $T_c = 8 \, \mu s = 8 	imes 10^{-6} \, s$. The angular frequency is $\omega_c = \frac{2\pi}{T_c} = \frac{2\pi}{8 	imes 10^{-6}} = 0.25 	imes 10^6 \pi = 2.5\pi 	imes 10^5 \, rad/s$.$4$. The general form of an amplitude modulated signal is $V(t) = (A_c + A_m \sin(\omega_m t)) \sin(\omega_c t)$.$5$. Substituting the values,we get $V(t) = (9 + 1 \sin(2\pi 	imes 10^4 t)) \sin(2.5\pi 	imes 10^5 t) \, V$.

An amplitude modulated signal is plotted below. Which one of the following best describes the above signal?

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