An amplitude modulated wave is modulated to $50\%$. What is the saving in power if the carrier as well as one of the sidebands are suppressed?

$A$ message signal of $3 \text{ kHz}$ is used to modulate a carrier signal of frequency $1 \text{ MHz}$ using amplitude modulation. The upper sideband frequency and bandwidth respectively are:

$A$ message signal of frequency $50 / \pi \text{ kHz}$ and peak voltage of $5 \text{ V}$ is used to modulate a carrier of frequency $1 \text{ MHz}$ and peak voltage $20 \text{ V}$. The modulation index is

An amplitude modulated signal is given by $V(t) = 10[1 + 0.6 \cos(2.2 \times 10^4 t)] \sin(5.5 \times 10^5 t)$, where $t$ is in seconds. The sideband frequencies (in $kHz$) are: [Given $\pi = 22/7$]

In amplitude modulation,the message signal $V_{m}(t) = 10 \sin(2 \pi \times 10^{5} t) \text{ V}$ and the carrier signal $V_{c}(t) = 20 \sin(2 \pi \times 10^{7} t) \text{ V}$. The modulated signal contains the message signal with lower sideband and upper sideband frequencies. Therefore,the bandwidth of the modulated signal is $\alpha \text{ kHz}$. The value of $\alpha$ is:

The amplitude of the side bands of the modulated signal, if the carrier signal and message signal amplitudes are $25 \,V$ and $5 \,V$ respectively, is (in $\,V$)