An angle has a measure equal to frac{5}{4} of | vedclass

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(A) Let the measure of the angle be $x^o$.Since the sum of complementary angles is $90^o$,the measure of its complementary angle is $(90 - x)^o$.Accor

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(A) Let the measure of the angle be $x^o$.Since the sum of complementary angles is $90^o$,the measure of its complementary angle is $(90 - x)^o$.According to the problem,the angle is $\frac{5}{4}$ times its complementary angle:$x = \frac{5}{4}(90 - x)$Multiply both sides by $4$:$4x = 5(90 - x)$$4x = 450 - 5x$Add $5x$ to both sides:$9x = 450$Divide by $9$:$x = 50$Therefore,the measure of the angle is $50^o$.

An angle has a measure equal to $\frac{5}{4}$ of the measure of its complementary angle. Find the measure of that angle. (in $^o$)

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