An aqueous solution of sodium nitrite on boil | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of $\alpha$-chlorosodium propionate $(CH_3CHClCOONa)$ with aqueous sodium nitrite $(NaNO_2)$ involves the displacement of the chlorin

Vedclass · Accepted Answer

Nitroethane

Vedclass · Answer

(B) The reaction of $\alpha$-chlorosodium propionate $(CH_3CHClCOONa)$ with aqueous sodium nitrite $(NaNO_2)$ involves the displacement of the chlorine atom by the nitrite group,followed by decarboxylation upon boiling. The reaction proceeds as follows: $CH_3CHClCOONa + NaNO_2 \rightarrow CH_3CH(NO_2)COONa + NaCl$ Upon boiling,the intermediate undergoes decarboxylation: $CH_3CH(NO_2)COONa \xrightarrow{\Delta} CH_3CH_2NO_2 + CO_2 + NaCl$ Thus,the final product is nitroethane.

An aqueous solution of sodium nitrite on boiling with $\alpha$-chlorosodium propionate gives:

Similar Questions

What is the $IUPAC$ name of the compound $CH_3-CH_2-NH-CH_3$?

Identify the structure of the compound which is responsible for the Bhopal gas tragedy.

$A$ secondary amine is:

The $IUPAC$ name of $CH_3-CH_2-CH(NH_2)-CH_3$ is:

The following compounds can be classified as $N,N$-dimethylpropan$-1-$amine,$N$-methylaniline,and aniline,respectively. Identify their classification as primary,secondary,or tertiary amines.

Vedclass Test Series

Exam Paper Generator

Online Exam Module