An army lost 10 % of its men in war,10 % of t | vedclass

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(A) Let the original strength of the army be $x$.After losing $10 \%$ in war,the remaining men are $x 	imes (1 - 0.10) = 0.9x$.After $10 \%$ of the r

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$1,000,000$

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(A) Let the original strength of the army be $x$.After losing $10 \%$ in war,the remaining men are $x 	imes (1 - 0.10) = 0.9x$.After $10 \%$ of the remaining died due to disease,the remaining men are $0.9x 	imes (1 - 0.10) = 0.9x 	imes 0.9 = 0.81x$.After $10 \%$ of the rest were declared disabled,the remaining active men are $0.81x 	imes (1 - 0.10) = 0.81x 	imes 0.9 = 0.729x$.Given that the final strength is $729,000$,we have $0.729x = 729,000$.Solving for $x$: $x = \frac{729,000}{0.729} = 1,000,000$.Therefore,the original strength of the army was $1,000,000$.

An army lost $10 \%$ of its men in war,$10 \%$ of the remaining died due to disease,and $10 \%$ of the rest were declared disabled. Thus,the strength of the army was reduced to $7,29,000$ active men. What was the original strength of the army?

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