An atom has 35 nucleons and an atomic number | vedclass

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(B) The atomic number $Z = 17$. The electronic configuration is $1s^2 2s^2 2p^6 3s^2 3p^5$.For $n = 2$,the subshells are $2s$ and $2p$.In $2s$ subshel

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$4$

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(B) The atomic number $Z = 17$. The electronic configuration is $1s^2 2s^2 2p^6 3s^2 3p^5$.For $n = 2$,the subshells are $2s$ and $2p$.In $2s$ subshell,$l = 0$,so $m = 0$. There are $2$ electrons in $2s$ orbital $(m = 0)$.In $2p$ subshell,$l = 1$,so $m = -1, 0, +1$. There are $6$ electrons in $2p$ subshell,with $2$ electrons in each orbital $(m = -1, 0, +1)$.Thus,the $2p$ orbital with $m = 0$ contains $2$ electrons.Total number of electrons with $n = 2$ and $m = 0$ is $2$ (from $2s$) $+ 2$ (from $2p$) $= 4$.

An atom has $35$ nucleons and an atomic number equal to $17$. The number of electrons with $n = 2$ and $m = 0$ in it is:

Similar Questions

Given,
$(A)$ $n=5, m_l=-1$
$(B)$ $n=3, l=2, m_l=-1, m_s=+\frac{1}{2}$
The maximum number of electron$(s)$ in an atom that can have the quantum numbers as given in $(A)$ and $(B)$ respectively are:

Which of the following sets of quantum numbers represents the orbital with the highest energy?

Which quantum number provides information about the shape of an orbital?

If $n = 3$,then which of the following values of $l$ is incorrect?

Which of the following sets of quantum numbers is not possible?

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