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(B) Power $P = 300 \, MW = 300 	imes 10^6 \, W$.Energy released per fission $E = 170 \, MeV = 170 	imes 10^6 	imes 1.6 	imes 10^{-19} \, J = 2.72

Vedclass · Accepted Answer

$4 	imes 10^{22}$

Vedclass · Answer

(B) Power $P = 300 \, MW = 300 	imes 10^6 \, W$.Energy released per fission $E = 170 \, MeV = 170 	imes 10^6 	imes 1.6 	imes 10^{-19} \, J = 2.72 	imes 10^{-11} \, J$.The number of fissions per second $n = \frac{P}{E} = \frac{300 	imes 10^6}{2.72 	imes 10^{-11}} \approx 1.103 	imes 10^{19} \, 	ext{fissions/sec}$.The number of fissions per hour $N = n 	imes 3600 \, 	ext{seconds} = 1.103 	imes 10^{19} 	imes 3600 \approx 3.97 	imes 10^{22} \approx 4 	imes 10^{22}$.

An atomic power nuclear reactor can deliver $300 \, MW$. The energy released due to the fission of each nucleus of uranium atom $U^{238}$ is $170 \, MeV$. The number of uranium atoms fissioned per hour will be:

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