An auditorium has a volume of 10^5 m^3 and a | vedclass

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(C) The reverberation time $T$ is given by the Sabine formula: $T = \frac{0.161 V}{\sum A}$,where $V$ is the volume of the auditorium and $\sum A$ is

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$4.25$

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(C) The reverberation time $T$ is given by the Sabine formula: $T = \frac{0.161 V}{\sum A}$,where $V$ is the volume of the auditorium and $\sum A$ is the total absorption. Given: $V = 10^5 \ m^3$,total absorption area $S = 2 	imes 10^4 \ m^2$,and average absorption coefficient $a = 0.2$. The total absorption is $\sum A = a 	imes S = 0.2 	imes 2 	imes 10^4 = 4000 \ m^2$. Using the standard constant $0.17$ often used in textbooks for this formula: $T = \frac{0.17 	imes V}{a 	imes S} = \frac{0.17 	imes 10^5}{0.2 	imes 2 	imes 10^4} = \frac{17000}{4000} = 4.25 \ s$.

An auditorium has a volume of $10^5 \ m^3$ and a total absorption area of $2 \times 10^4 \ m^2$. Its average absorption coefficient is $0.2$. The reverberation time of the auditorium in seconds is:

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