(B) Given: Dipole moment $p = 6 \times 10^{-6} \ Cm$,Electric field $E = 10^6 \ V/m$.The work done $W$ in rotating an electric dipole in a uniform ele

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(B) Given: Dipole moment $p = 6 \times 10^{-6} \ Cm$,Electric field $E = 10^6 \ V/m$.The work done $W$ in rotating an electric dipole in a uniform electric field is given by $W = U_f - U_i = -pE \cos \theta_f - (-pE \cos \theta_i) = pE(\cos \theta_i - \cos \theta_f)$.Initially,the dipole is parallel to the field,so $\theta_i = 0^\circ$.Finally,the dipole is opposite to the field,so $\theta_f = 180^\circ$.Substituting the values: $W = pE(\cos 0^\circ - \cos 180^\circ) = pE(1 - (-1)) = 2pE$.$W = 2 \times (6 \times 10^{-6}) \times 10^6 = 12 \ J$.

Class 12 Physics Electrostatic Potential and Capacitance Electric potential and Potential Energy of dipole

Medium

An electric dipole of dipole moment $6 \times 10^{-6} \ Cm$ is placed in a uniform electric field of magnitude $10^6 \ V/m$. Initially,the dipole moment is parallel to the electric field. The work that needs to be done on the dipole to make its dipole moment opposite to the field will be . . . . . . $J$.

JEE MAIN 2025 All JEE MAIN

A
$11$
B
$12$
C
$16$
D
$19$

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Electrostatic Potential and Capacitance

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Electric potential and Potential Energy of dipole

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