An electric dipole of length 4 cm is placed | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The torque $	au$ experienced by an electric dipole in a uniform electric field $E$ is given by the formula: $	au = pE \sin 	heta$,where $p = q

Vedclass · Accepted Answer

$2.5 	imes 10^{10} \ N/C$

Vedclass · Answer

(A) The torque $	au$ experienced by an electric dipole in a uniform electric field $E$ is given by the formula: $	au = pE \sin 	heta$,where $p = q 	imes \ell$ is the dipole moment.Given: Charge $q = 8 	imes 10^{-9} \ C$,length $\ell = 4 	imes 10^{-2} \ m$,angle $	heta = 60^{\circ}$,and torque $	au = 4 \sqrt{3} \ Nm$.Substituting the values into the formula: $	au = (q \ell) E \sin 	heta$.$4 \sqrt{3} = (8 	imes 10^{-9}) 	imes (4 	imes 10^{-2}) 	imes E 	imes \sin 60^{\circ}$.Since $\sin 60^{\circ} = \frac{\sqrt{3}}{2}$,we have:$4 \sqrt{3} = (32 	imes 10^{-11}) 	imes E 	imes \frac{\sqrt{3}}{2}$.$4 \sqrt{3} = (16 	imes 10^{-11}) 	imes \sqrt{3} 	imes E$.Dividing both sides by $\sqrt{3}$:$4 = 16 	imes 10^{-11} 	imes E$.$E = \frac{4}{16 	imes 10^{-11}} = 0.25 	imes 10^{11} = 2.5 	imes 10^{10} \ N/C$.

An electric dipole of length $4 \ cm$ is placed with its axis making an angle of $60^{\circ}$ with a uniform electric field. It experiences a torque of $4 \sqrt{3} \ Nm$. Calculate the magnitude of the electric field. (The dipole has charges $\pm 8 \ nC$)

Similar Questions

$A$ and $B$ are two points on the axis and the perpendicular bisector respectively of an electric dipole. $A$ and $B$ are far away from the dipole and at equal distance from it. The electric fields at $A$ and $B$ are $\vec{E}_A$ and $\vec{E}_B$.

$A$ dipole having a dipole moment $p = 4 \, C-m$ is placed at the origin along the $x$-axis. $A$ point charge $q = 8 \, \mu C$ is fixed at $(4, 0, 0)$. Now,the dipole is rotated by an angle of $\frac{\pi}{2}$. Find the work done (in $mJ$) in rotating the dipole.

Three identical dipoles are arranged as shown below. What will be the net electric field at $P$ $\left( {k = \frac{1}{{4\pi {\varepsilon _0}}}} \right)$?

An electric dipole with dipole moment $4 \times 10^{-9} \;C \,m$ is aligned at $30^{\circ}$ with the direction of a uniform electric field of magnitude $5 \times 10^{4} \;N\,C ^{-1}$. Calculate the magnitude of the torque acting on the dipole.

An electric dipole consisting of two opposite charges of $2 \times 10^{-6} \, C$ each,separated by a distance of $3 \, cm$,is placed in an electric field of $2 \times 10^5 \, N/C$. The maximum torque on the dipole will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module