An electric dipole with dipole moment 4 times | vedclass

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Question

(B) The torque $	au$ acting on an electric dipole in a uniform electric field is given by the formula: $	au = pE \sin 	heta$.Given values are: Dipo

Vedclass · Accepted Answer

$1.73 	imes 10^{-4} 	ext{ Nm}$

Vedclass · Answer

(B) The torque $	au$ acting on an electric dipole in a uniform electric field is given by the formula: $	au = pE \sin 	heta$.Given values are: Dipole moment $p = 4 	imes 10^{-9} 	ext{ Cm}$Electric field $E = 5 	imes 10^4 	ext{ NC}^{-1}$Angle $	heta = 60^{\circ}$Substituting these values into the formula:$	au = (4 	imes 10^{-9}) 	imes (5 	imes 10^4) 	imes \sin 60^{\circ}$$	au = 20 	imes 10^{-5} 	imes \frac{\sqrt{3}}{2}$$	au = 10 	imes 10^{-5} 	imes 1.732$$	au = 1.732 	imes 10^{-4} 	ext{ Nm}$Thus,the magnitude of the torque is $1.73 	imes 10^{-4} 	ext{ Nm}$.

An electric dipole with dipole moment $4 \times 10^{-9} \text{ Cm}$ is aligned at $60^{\circ}$ with the direction of a uniform electric field of magnitude $5 \times 10^4 \text{ NC}^{-1}$. Calculate the magnitude of the torque acting on the dipole.

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