An electric dipole with dipole moment 2 times | vedclass

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Question

(A) The torque $	au$ acting on an electric dipole in a uniform electric field is given by the formula: $	au = pE \sin 	heta$. Given: Dipole moment

Vedclass · Accepted Answer

$10^{-6} 	ext{ N m}$

Vedclass · Answer

(A) The torque $	au$ acting on an electric dipole in a uniform electric field is given by the formula: $	au = pE \sin 	heta$. Given: Dipole moment $p = 2 	imes 10^{-10} 	ext{ C m}$. Electric field $E = 10^4 	ext{ N C}^{-1}$. Angle $	heta = 30^{\circ}$. Substituting the values into the formula: $	au = (2 	imes 10^{-10}) 	imes (10^4) 	imes \sin(30^{\circ})$. Since $\sin(30^{\circ}) = 0.5$: $	au = 2 	imes 10^{-6} 	imes 0.5 = 1 	imes 10^{-6} 	ext{ N m}$. Therefore,the magnitude of the torque is $10^{-6} 	ext{ N m}$.

An electric dipole with dipole moment $2 \times 10^{-10} \text{ C m}$ is aligned at an angle $30^{\circ}$ with the direction of a uniform electric field of $10^4 \text{ N C}^{-1}$. The magnitude of the torque acting on the dipole is:

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