An electric discharge is passed through a mix | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction is $2H_{2(g)} + O_{2(g)} 	o 2H_2O$. $(i)$ At room temperature,$H_2O$ exists as a liquid and its volume is negligible. $H_2$ is the l

Vedclass · Accepted Answer

$(i) \, 25 \, c.c., \, (ii) \, 75 \, c.c.$

Vedclass · Answer

(C) The reaction is $2H_{2(g)} + O_{2(g)} 	o 2H_2O$. $(i)$ At room temperature,$H_2O$ exists as a liquid and its volume is negligible. $H_2$ is the limiting reagent ($50 \, mL$ of $H_2$ reacts with $25 \, mL$ of $O_2$). Remaining $O_2 = 50 - 25 = 25 \, mL$. Total volume of gas = $25 \, c.c.$ $(ii)$ At $110 \, ^oC$,$H_2O$ exists as a gas (steam). $2H_{2(g)} + O_{2(g)} 	o 2H_2O_{(g)}$. Remaining $O_2 = 25 \, mL$,produced $H_2O_{(g)} = 50 \, mL$. Total volume of gas = $25 + 50 = 75 \, c.c.$

An electric discharge is passed through a mixture containing $50 \, c.c.$ of $O_2$ and $50 \, c.c.$ of $H_2$. The volume of the gases formed $(i)$ at room temperature and $(ii)$ at $110 \, ^oC$ will be

Similar Questions

How many moles of $CO_2$ will be produced from $4 \ g$ carbon and $4 \ g$ oxygen in the following reaction?
$C + O_2 \rightarrow CO_2$

If $0.50 \ mol$ of $CaCl_2$ is mixed with $0.20 \ mol$ of $Na_3PO_4$,the maximum number of moles of $Ca_3(PO_4)_2$ which can be formed,is

For the reaction $A + 2B \rightarrow C$,$5 \ \text{mol}$ of $A$ and $8 \ \text{mol}$ of $B$ produce how many moles of $C$?

For the reaction,$2Fe(NO_3)_3 + 3Na_2CO_3 \to Fe_2(CO_3)_3 + 6NaNO_3$. Initially,if $2.5 \ mol$ of $Fe(NO_3)_3$ and $3.6 \ mol$ of $Na_2CO_3$ are taken. If $6.3 \ mol$ of $NaNO_3$ is obtained,then the $\%$ yield of the given reaction is:

What is a limiting reagent?

Vedclass Test Series

Exam Paper Generator

Online Exam Module