An electric fan has blades of length 30 , cm | vedclass

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(B) The angular velocity $\omega$ is given by $\omega = 2 \pi f$,where $f$ is the frequency in $Hz$.Given $f = 1200 \, r.p.m. = \frac{1200}{60} \, r.p

Vedclass · Accepted Answer

$4740$

Vedclass · Answer

(B) The angular velocity $\omega$ is given by $\omega = 2 \pi f$,where $f$ is the frequency in $Hz$.Given $f = 1200 \, r.p.m. = \frac{1200}{60} \, r.p.s. = 20 \, Hz$.Thus,$\omega = 2 \pi 	imes 20 = 40 \pi \, rad/s$.The centripetal acceleration $a$ is given by $a = \omega^2 r$.Given $r = 30 \, cm = 0.3 \, m$.$a = (40 \pi)^2 	imes 0.3 = 1600 \pi^2 	imes 0.3$.Using $\pi^2 \approx 9.8696$,we get $a = 1600 	imes 9.8696 	imes 0.3 = 4737.4 \, m/s^2$.Rounding to the nearest given option,the acceleration is approximately $4740 \, m/s^2$.

An electric fan has blades of length $30 \, cm$ as measured from the axis of rotation. If the fan is rotating at $1200 \, r.p.m.$,the acceleration of a point on the tip of the blade is approximately ........ $m/s^2$.

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