An electric iron of resistance 20, Omega take | vedclass

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Question

(D) The amount of heat $(H)$ produced is given by Joule's law of heating as $H = I^2Rt$.Given:Resistance,$R = 20\, \Omega$Current,$I = 5\, A$Time,$t =

Vedclass · Accepted Answer

$1.5 	imes 10^4\, J$

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(D) The amount of heat $(H)$ produced is given by Joule's law of heating as $H = I^2Rt$.Given:Resistance,$R = 20\, \Omega$Current,$I = 5\, A$Time,$t = 30\, s$Using the formula:$H = (5)^2 	imes 20 	imes 30$$H = 25 	imes 20 	imes 30$$H = 500 	imes 30$$H = 15000\, J$$H = 1.5 	imes 10^4\, J$Therefore,the amount of heat developed in the electric iron is $1.5 	imes 10^4\, J$.

An electric iron of resistance $20\, \Omega$ takes a current of $5\, A$. Calculate the heat developed in $30\, s$.

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