An electron (charge = 1.6 times 10^{-19} text | vedclass

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Question

(D) The energy $E$ acquired by a charged particle accelerated through a potential difference $V$ is given by the formula $E = qV$.Here,the charge of t

Vedclass · Accepted Answer

$1.6 	imes 10^{-14} 	ext{ J}$

Vedclass · Answer

(D) The energy $E$ acquired by a charged particle accelerated through a potential difference $V$ is given by the formula $E = qV$.Here,the charge of the electron is $q = 1.6 	imes 10^{-19} 	ext{ C}$.The potential difference is $V = 1,00,000 	ext{ V} = 10^5 	ext{ V}$.Substituting these values into the formula:$E = (1.6 	imes 10^{-19} 	ext{ C}) 	imes (10^5 	ext{ V})$$E = 1.6 	imes 10^{-19+5} 	ext{ J}$$E = 1.6 	imes 10^{-14} 	ext{ J}$.Therefore,the correct option is $D$.

An electron (charge = $1.6 \times 10^{-19} \text{ C}$) is accelerated through a potential difference of $1,00,000 \text{ V}$. The energy acquired by the electron is:

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