An electron experiences a force equal to its | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The force experienced by an electron in an electric field is given by $F = qE$,where $q = e$ is the charge of the electron and $E$ is the electric

Vedclass · Accepted Answer

$5.5 	imes 10^{-11} \ N/C$

Vedclass · Answer

(C) The force experienced by an electron in an electric field is given by $F = qE$,where $q = e$ is the charge of the electron and $E$ is the electric field intensity.Given that the force is equal to the weight of the electron,we have $F = mg$,where $m$ is the mass of the electron $(m \approx 9.1 	imes 10^{-31} \ kg)$ and $g$ is the acceleration due to gravity $(g \approx 9.8 \ m/s^2)$.Equating the two,we get $eE = mg$,which implies $E = \frac{mg}{e}$.Substituting the values: $E = \frac{9.1 	imes 10^{-31} \ kg 	imes 9.8 \ m/s^2}{1.6 	imes 10^{-19} \ C}$.$E \approx \frac{89.18 	imes 10^{-31}}{1.6 	imes 10^{-19}} \ N/C \approx 5.57 	imes 10^{-11} \ N/C$.Rounding to the nearest given option,the intensity of the field is $5.5 	imes 10^{-11} \ N/C$.

An electron experiences a force equal to its weight when placed in an electric field. The intensity of the field will be

Similar Questions

An electron is accelerated through a potential difference $(p.d.)$ of $45.5 \ V$. The velocity acquired by it is (in $m \ s^{-1}$)

What is the magnitude of the upward electric field (in $V/m$) required to keep a coin of mass $10^{-6} \ kg$ and charge $10^{-6} \ C$ in equilibrium? (Take $g = 10 \ m/s^2$)

Calculate the work done by the electrostatic force on an electron moving in a circular orbit around the nucleus.

The figure shows the tracks of three charged particles in a uniform electrostatic field. Give the signs of the three charges. Which particle has the highest charge-to-mass ratio?

$A$ particle with charge $q$ approaches a fixed particle with charge $Q$ with an initial velocity $v$. It comes to a stop at a closest distance $r$ from $Q$. If the particle $q$ is given an initial velocity $2v$,the closest distance will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module